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		<title>LaTeX</title>
		<link>http://matemania.wordpress.com/2011/12/24/latex-2/</link>
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		<pubDate>Sat, 24 Dec 2011 16:30:40 +0000</pubDate>
		<dc:creator>edyjo</dc:creator>
				<category><![CDATA[LaTeX]]></category>
		<category><![CDATA[Matematika Dasar]]></category>

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		<description><![CDATA[x &#60; 0$;}\\ \alpha + x, &#38;\text{if $0 \leq x \leq 1$;}\\ x^{2}, &#38;\text{otherwise.} \end{cases} \] $<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=matemania.wordpress.com&amp;blog=2732517&amp;post=376&amp;subd=matemania&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><img src='http://s0.wp.com/latex.php?latex=%3C%2Fp%3E++%3Cp%3E%5C%5B+++%3Cbr+%2F%3Ef%28x%29%3D++++%3Cbr+%2F%3E%5Cbegin%7Bcases%7D++++%3Cbr+%2F%3E-x%5E%7B2%7D%2C+%26%5Ctext%7Bif+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='&lt;/p&gt;  &lt;p&gt;&#92;[   &lt;br /&gt;f(x)=    &lt;br /&gt;&#92;begin{cases}    &lt;br /&gt;-x^{2}, &amp;&#92;text{if ' title='&lt;/p&gt;  &lt;p&gt;&#92;[   &lt;br /&gt;f(x)=    &lt;br /&gt;&#92;begin{cases}    &lt;br /&gt;-x^{2}, &amp;&#92;text{if ' class='latex' />x &lt; 0$;}\\    <br />\alpha + x, &amp;\text{if $0 \leq x \leq 1$;}\\    <br />x^{2}, &amp;\text{otherwise.}    <br />\end{cases}    <br />\]</p>
<p>$</p>
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		<title>Problem #4</title>
		<link>http://matemania.wordpress.com/2011/12/13/problem-4/</link>
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		<pubDate>Tue, 13 Dec 2011 16:07:09 +0000</pubDate>
		<dc:creator>edyjo</dc:creator>
				<category><![CDATA[LaTeX]]></category>
		<category><![CDATA[Matematika Dasar]]></category>

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		<description><![CDATA[In the figure below, PQRS is rectangle. What is value of ? Solusi Berdasarkan kesebangunan segitiga-segitiga dan teorema Phytagoras, diperoleh: Sehingga,<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=matemania.wordpress.com&amp;blog=2732517&amp;post=369&amp;subd=matemania&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>In the figure below, PQRS is rectangle. What is value of <img src='http://s0.wp.com/latex.php?latex=a+%2B+b+%2B+c+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='a + b + c ' title='a + b + c ' class='latex' /> ?</p>
<p><a href="http://matemania.files.wordpress.com/2011/12/problem-4.png"><img src="http://matemania.files.wordpress.com/2011/12/problem-4.png?w=610" alt="" title="problem #4"   class="alignnone size-full wp-image-370" /></a></p>
<p><strong>Solusi</strong></p>
<p>Berdasarkan kesebangunan segitiga-segitiga dan teorema Phytagoras, diperoleh:</p>
<p><img src='http://s0.wp.com/latex.php?latex=a%5E2+%3D+9+%5Ccdot+%289+%2B+16%29+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='a^2 = 9 &#92;cdot (9 + 16) ' title='a^2 = 9 &#92;cdot (9 + 16) ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=a%5E2+%3D+225+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='a^2 = 225 ' title='a^2 = 225 ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=a+%3D+15+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='a = 15 ' title='a = 15 ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=b%5E2+%3D+9+%5Ctimes+16+%3D+144+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='b^2 = 9 &#92;times 16 = 144 ' title='b^2 = 9 &#92;times 16 = 144 ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=b+%3D+12+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='b = 12 ' title='b = 12 ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=c%5E2+%3D+16+%5Ccdot+%289+%2B+16%29+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='c^2 = 16 &#92;cdot (9 + 16) ' title='c^2 = 16 &#92;cdot (9 + 16) ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=c%5E2+%3D+400+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='c^2 = 400 ' title='c^2 = 400 ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=c+%3D+20+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='c = 20 ' title='c = 20 ' class='latex' /></p>
<p>Sehingga, <img src='http://s0.wp.com/latex.php?latex=a+%2B+b+%2B+c+%3D+...+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='a + b + c = ... ' title='a + b + c = ... ' class='latex' /> </p>
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			<media:title type="html">problem #4</media:title>
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		<title>Problem #3</title>
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		<pubDate>Tue, 13 Dec 2011 15:36:30 +0000</pubDate>
		<dc:creator>edyjo</dc:creator>
				<category><![CDATA[LaTeX]]></category>
		<category><![CDATA[Matematika Dasar]]></category>

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		<description><![CDATA[Determine the value of: SOLUSI Ingat kesamaan lebih khusus, jika , maka , sehingga: yang merupakan deret hitung dengan suku pertama, dan beda, . maka jumlah 50 suku pertama adalah: Jadi,<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=matemania.wordpress.com&amp;blog=2732517&amp;post=366&amp;subd=matemania&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Determine the value of:</p>
<p><img src='http://s0.wp.com/latex.php?latex=100%5E2+-+99%5E2+%2B+98%5E2+-+97%5E2+%2B+96%5E2+-+95%5E2+%2B+%5Cldots+%2B+4%5E2+-+3%5E2+%2B+2%5E2+-+1%5E2+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='100^2 - 99^2 + 98^2 - 97^2 + 96^2 - 95^2 + &#92;ldots + 4^2 - 3^2 + 2^2 - 1^2 ' title='100^2 - 99^2 + 98^2 - 97^2 + 96^2 - 95^2 + &#92;ldots + 4^2 - 3^2 + 2^2 - 1^2 ' class='latex' /></p>
<p><b>SOLUSI</b></p>
<p>Ingat kesamaan</p>
<p><img src='http://s0.wp.com/latex.php?latex=a%5E2+-+b%5E2+%3D+%28a+%2B+b%29%28a+-+b%29+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='a^2 - b^2 = (a + b)(a - b) ' title='a^2 - b^2 = (a + b)(a - b) ' class='latex' /></p>
<p>lebih khusus, jika <img src='http://s0.wp.com/latex.php?latex=a+-+b+%3D+1+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='a - b = 1 ' title='a - b = 1 ' class='latex' />, maka</p>
<p><img src='http://s0.wp.com/latex.php?latex=a%5E2+-+b%5E2+%3D+a+%2B+b+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='a^2 - b^2 = a + b ' title='a^2 - b^2 = a + b ' class='latex' />, sehingga:</p>
<p><img src='http://s0.wp.com/latex.php?latex=100%5E2+-+99%5E2+%2B+98%5E2+-+97%5E2+%2B+96%5E2+-+95%5E2+%2B+%5Cldots+%2B+4%5E2+-+3%5E2+%2B+2%5E2+-+1%5E2+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='100^2 - 99^2 + 98^2 - 97^2 + 96^2 - 95^2 + &#92;ldots + 4^2 - 3^2 + 2^2 - 1^2 ' title='100^2 - 99^2 + 98^2 - 97^2 + 96^2 - 95^2 + &#92;ldots + 4^2 - 3^2 + 2^2 - 1^2 ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%3D+%28100+%2B+99%29+%2B+%2898+%2B+97%29+%2B+%2896+%2B+95%29+%2B+%5Ccdots+%2B+%284+%2B+3%29+%2B+%282+%2B+1%29+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='= (100 + 99) + (98 + 97) + (96 + 95) + &#92;cdots + (4 + 3) + (2 + 1) ' title='= (100 + 99) + (98 + 97) + (96 + 95) + &#92;cdots + (4 + 3) + (2 + 1) ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%3D+199+%2B+195+%2B+191+%2B+%5Ccdots+%2B+7+%2B+3+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='= 199 + 195 + 191 + &#92;cdots + 7 + 3 ' title='= 199 + 195 + 191 + &#92;cdots + 7 + 3 ' class='latex' /></p>
<p>yang merupakan deret hitung dengan suku pertama, <img src='http://s0.wp.com/latex.php?latex=a+%3D+3+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='a = 3 ' title='a = 3 ' class='latex' /> dan beda, <img src='http://s0.wp.com/latex.php?latex=b+%3D+4+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='b = 4 ' title='b = 4 ' class='latex' />.</p>
<p><img src='http://s0.wp.com/latex.php?latex=a+%2B+%28n+-+1%29b+%3D+199+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='a + (n - 1)b = 199 ' title='a + (n - 1)b = 199 ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=3+%2B+%28n+-+1%294+%3D+199+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='3 + (n - 1)4 = 199 ' title='3 + (n - 1)4 = 199 ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=4n+%3D+200+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='4n = 200 ' title='4n = 200 ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=n+%3D+50+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='n = 50 ' title='n = 50 ' class='latex' /></p>
<p>maka jumlah 50 suku pertama adalah:</p>
<p><img src='http://s0.wp.com/latex.php?latex=S_%7Bn%7D+%3D+%5Cfrac+%7B1%7D%7B2%7D+%5Ccdot+n+%282a+%2B+%28n+-+1%29b%29+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='S_{n} = &#92;frac {1}{2} &#92;cdot n (2a + (n - 1)b) ' title='S_{n} = &#92;frac {1}{2} &#92;cdot n (2a + (n - 1)b) ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=S_%7B50%7D+%3D+%5Cfrac+%7B1%7D%7B2%7D+%5Ccdot+50+%282+%5Ccdot+3+%2B+%2850+-+1%29+%5Ccdot+4%29+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='S_{50} = &#92;frac {1}{2} &#92;cdot 50 (2 &#92;cdot 3 + (50 - 1) &#92;cdot 4) ' title='S_{50} = &#92;frac {1}{2} &#92;cdot 50 (2 &#92;cdot 3 + (50 - 1) &#92;cdot 4) ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=S_%7B50%7D+%3D+25+%5Ccdot+%286+%2B+196%29+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='S_{50} = 25 &#92;cdot (6 + 196) ' title='S_{50} = 25 &#92;cdot (6 + 196) ' class='latex' /></p>
<p>Jadi, <img src='http://s0.wp.com/latex.php?latex=S_%7B50%7D+%3D+%5Ccdots+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='S_{50} = &#92;cdots ' title='S_{50} = &#92;cdots ' class='latex' /></p>
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		<title>Problem #2</title>
		<link>http://matemania.wordpress.com/2011/12/13/problem-2/</link>
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		<pubDate>Tue, 13 Dec 2011 14:58:14 +0000</pubDate>
		<dc:creator>edyjo</dc:creator>
				<category><![CDATA[LaTeX]]></category>
		<category><![CDATA[Matematika Dasar]]></category>

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		<description><![CDATA[Value sum the first ten terms of sequence numbers SOLUSI Perhatikan pola berikut: Dengan demikian,<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=matemania.wordpress.com&amp;blog=2732517&amp;post=357&amp;subd=matemania&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Value sum the first ten terms of sequence numbers<br />
<img src='http://s0.wp.com/latex.php?latex=%5Cfrac+%7B1%7D%7B1+%5Ccdot+2%7D+%2B+%5Cfrac+%7B1%7D%7B2+%5Ccdot+3%7D+%2B+%5Cfrac+%7B1%7D%7B3+%5Ccdot+4%7D+%2B+%5Cfrac+%7B1%7D%7B4+%5Ccdot+5%7D+%2B+%5Ccdots+%2B+%5Cfrac+%7B1%7D%7B9+%5Ccdot+10%7D+%2B+%5Cfrac+%7B1%7D%7B10+%5Ccdot+11%7D+%3D+...+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='&#92;frac {1}{1 &#92;cdot 2} + &#92;frac {1}{2 &#92;cdot 3} + &#92;frac {1}{3 &#92;cdot 4} + &#92;frac {1}{4 &#92;cdot 5} + &#92;cdots + &#92;frac {1}{9 &#92;cdot 10} + &#92;frac {1}{10 &#92;cdot 11} = ... ' title='&#92;frac {1}{1 &#92;cdot 2} + &#92;frac {1}{2 &#92;cdot 3} + &#92;frac {1}{3 &#92;cdot 4} + &#92;frac {1}{4 &#92;cdot 5} + &#92;cdots + &#92;frac {1}{9 &#92;cdot 10} + &#92;frac {1}{10 &#92;cdot 11} = ... ' class='latex' /></p>
<p><strong>SOLUSI</strong><br />
Perhatikan pola berikut:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cfrac+%7B1%7D%7B1+%5Ccdot+2%7D+%3D+%5Cfrac+%7B1%7D%7B2%7D+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='&#92;frac {1}{1 &#92;cdot 2} = &#92;frac {1}{2} ' title='&#92;frac {1}{1 &#92;cdot 2} = &#92;frac {1}{2} ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cfrac+%7B1%7D%7B1+%5Ccdot+2%7D+%2B+%5Cfrac+%7B1%7D%7B2+%5Ccdot+3%7D+%3D+%5Cfrac+%7B2%7D%7B3%7D+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='&#92;frac {1}{1 &#92;cdot 2} + &#92;frac {1}{2 &#92;cdot 3} = &#92;frac {2}{3} ' title='&#92;frac {1}{1 &#92;cdot 2} + &#92;frac {1}{2 &#92;cdot 3} = &#92;frac {2}{3} ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cfrac+%7B1%7D%7B1+%5Ccdot+2%7D+%2B+%5Cfrac+%7B1%7D%7B2+%5Ccdot+3%7D+%2B+%5Cfrac+%7B1%7D%7B3+%5Ccdot+4%7D+%3D+%5Cfrac+%7B3%7D%7B4%7D+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='&#92;frac {1}{1 &#92;cdot 2} + &#92;frac {1}{2 &#92;cdot 3} + &#92;frac {1}{3 &#92;cdot 4} = &#92;frac {3}{4} ' title='&#92;frac {1}{1 &#92;cdot 2} + &#92;frac {1}{2 &#92;cdot 3} + &#92;frac {1}{3 &#92;cdot 4} = &#92;frac {3}{4} ' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cvdots+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='&#92;vdots ' title='&#92;vdots ' class='latex' /></p>
<p>Dengan demikian, </p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cfrac+%7B1%7D%7B1+%5Ccdot+2%7D+%2B+%5Cfrac+%7B1%7D%7B2+%5Ccdot+3%7D+%2B+%5Cfrac+%7B1%7D%7B3+%5Ccdot+4%7D+%2B+%5Cfrac+%7B1%7D%7B4+%5Ccdot+5%7D+%2B+%5Ccdots+%2B+%5Cfrac+%7B1%7D%7B9+%5Ccdot+10%7D+%2B+%5Cfrac+%7B1%7D%7B10+%5Ccdot+11%7D+%3D+%5Cfrac+%7B..%7D%7B..%7D+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='&#92;frac {1}{1 &#92;cdot 2} + &#92;frac {1}{2 &#92;cdot 3} + &#92;frac {1}{3 &#92;cdot 4} + &#92;frac {1}{4 &#92;cdot 5} + &#92;cdots + &#92;frac {1}{9 &#92;cdot 10} + &#92;frac {1}{10 &#92;cdot 11} = &#92;frac {..}{..} ' title='&#92;frac {1}{1 &#92;cdot 2} + &#92;frac {1}{2 &#92;cdot 3} + &#92;frac {1}{3 &#92;cdot 4} + &#92;frac {1}{4 &#92;cdot 5} + &#92;cdots + &#92;frac {1}{9 &#92;cdot 10} + &#92;frac {1}{10 &#92;cdot 11} = &#92;frac {..}{..} ' class='latex' /></p>
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		<title>Problem #1</title>
		<link>http://matemania.wordpress.com/2011/12/13/problem-1/</link>
		<comments>http://matemania.wordpress.com/2011/12/13/problem-1/#comments</comments>
		<pubDate>Tue, 13 Dec 2011 14:37:06 +0000</pubDate>
		<dc:creator>edyjo</dc:creator>
				<category><![CDATA[LaTeX]]></category>
		<category><![CDATA[Matematika Dasar]]></category>

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		<description><![CDATA[Eleven students have a math test with the average score 65. The difference between the highest and the lowest scores is 20. If the highest and the lowest scores are ignored then average is 63. The highest score is &#8230; Solusi Nilai 11 siswa, misalkan x1, x2, &#8230;, x11. Reratanya 65. atau (pers. i) Misalkan x1 nilai [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=matemania.wordpress.com&amp;blog=2732517&amp;post=355&amp;subd=matemania&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Eleven students have a math test with the average score 65. The difference between the highest and the lowest scores is 20. If the highest and the lowest scores are ignored then average is 63. The highest score is &#8230;</p>
<p><strong>Solusi</strong><br />
Nilai 11 siswa, misalkan x<sub>1</sub>, x<sub>2</sub>, &#8230;, x<sub>11</sub>. Reratanya 65.<br />
<img src='http://s0.wp.com/latex.php?latex=%5Cfrac+%7Bx_%7B1%7D+%2B+x_%7B2%7D+%2B+...+%2B+x_%7B11%7D%7D%7B11%7D+%3D+65+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='&#92;frac {x_{1} + x_{2} + ... + x_{11}}{11} = 65 ' title='&#92;frac {x_{1} + x_{2} + ... + x_{11}}{11} = 65 ' class='latex' /><br />
atau<br />
<img src='http://s0.wp.com/latex.php?latex=x_%7B1%7D+%2B+x_%7B2%7D+%2B+...+%2B+x_%7B11%7D+%3D+65+%5Ctimes+11+%3D+715+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='x_{1} + x_{2} + ... + x_{11} = 65 &#92;times 11 = 715 ' title='x_{1} + x_{2} + ... + x_{11} = 65 &#92;times 11 = 715 ' class='latex' /> (pers. i)</p>
<p>Misalkan x<sub>1</sub> nilai tertinggi dan x<sub>11</sub> nilai terendah, selisihnya 20.<br />
<img src='http://s0.wp.com/latex.php?latex=x_%7B1%7D+-+x_%7B11%7D+%3D+20+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='x_{1} - x_{11} = 20 ' title='x_{1} - x_{11} = 20 ' class='latex' /> (pers. ii)</p>
<p>Rerata nilai tanpa menyertakan nilai tertinggi dan nilai terendah adalah 63.<br />
<img src='http://s0.wp.com/latex.php?latex=%5Cfrac+%7Bx_%7B2%7D+%2B+x_%7B3%7D+%2B+...+%2B+x_%7B10%7D%7D%7B9%7D+%3D+63+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='&#92;frac {x_{2} + x_{3} + ... + x_{10}}{9} = 63 ' title='&#92;frac {x_{2} + x_{3} + ... + x_{10}}{9} = 63 ' class='latex' /><br />
atau<br />
<img src='http://s0.wp.com/latex.php?latex=x_%7B2%7D+%2B+x_%7B3%7D+%2B+...+%2B+x_%7B10%7D+%3D+63+%5Ctimes+9+%3D+567+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='x_{2} + x_{3} + ... + x_{10} = 63 &#92;times 9 = 567 ' title='x_{2} + x_{3} + ... + x_{10} = 63 &#92;times 9 = 567 ' class='latex' /> (pers. iii)</p>
<p>Substitusi pers. iii ke pers. i<br />
<img src='http://s0.wp.com/latex.php?latex=x_%7B1%7D+%2B+x_%7B2%7D+%2B+...+%2B+x_%7B10%7D+%2B+x_%7B11%7D+%3D+715+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='x_{1} + x_{2} + ... + x_{10} + x_{11} = 715 ' title='x_{1} + x_{2} + ... + x_{10} + x_{11} = 715 ' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=x_%7B1%7D+%2B+x_%7B11%7D+%2B+%28x_%7B2%7D+%2B+...+%2B+x_%7B10%7D%29+%3D+715+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='x_{1} + x_{11} + (x_{2} + ... + x_{10}) = 715 ' title='x_{1} + x_{11} + (x_{2} + ... + x_{10}) = 715 ' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=x_%7B1%7D+%2B+x_%7B11%7D+%2B+567+%3D+715+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='x_{1} + x_{11} + 567 = 715 ' title='x_{1} + x_{11} + 567 = 715 ' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=x_%7B1%7D+%2B+x_%7B11%7D+%3D+148+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='x_{1} + x_{11} = 148 ' title='x_{1} + x_{11} = 148 ' class='latex' /> (pers. iv)</p>
<p>Berdasarkan pers. ii dan pers. iv<br />
<img src='http://s0.wp.com/latex.php?latex=x_%7B1%7D+%2B+x_%7B11%7D+%3D+148+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='x_{1} + x_{11} = 148 ' title='x_{1} + x_{11} = 148 ' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=x_%7B1%7D+-+x_%7B11%7D+%3D+20+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='x_{1} - x_{11} = 20 ' title='x_{1} - x_{11} = 20 ' class='latex' /></p>
<p>Eliminasi <img src='http://s0.wp.com/latex.php?latex=x_%7B11%7D+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='x_{11} ' title='x_{11} ' class='latex' />, maka diperoleh:</p>
<p><img src='http://s0.wp.com/latex.php?latex=2x_%7B1%7D+%3D+168+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='2x_{1} = 168 ' title='2x_{1} = 168 ' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=x_%7B1%7D+%3D+84+&amp;bg=f7f3ed&amp;fg=121212&amp;s=0' alt='x_{1} = 84 ' title='x_{1} = 84 ' class='latex' /></p>
<p>Jadi, nilai tertinggi = 84.<br />
&nbsp;</p>
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		<title>Bermain Tebak Bilangan</title>
		<link>http://matemania.wordpress.com/2011/07/30/bermain-tebak-bilangan/</link>
		<comments>http://matemania.wordpress.com/2011/07/30/bermain-tebak-bilangan/#comments</comments>
		<pubDate>Sat, 30 Jul 2011 19:30:36 +0000</pubDate>
		<dc:creator>edyjo</dc:creator>
				<category><![CDATA[Matematika Dasar]]></category>
		<category><![CDATA[pakarti]]></category>
		<category><![CDATA[Tips]]></category>

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		<description><![CDATA[Pada bahasan sebelumnya, tebak bilangan, saya sudah memberikan tautan (link) untuk mengunduh atau memainkan file presentasi tebak bilangan. Dalam artikel tersebut tidak (atau belum) diuraikan cara memainkan dan cara menebaknya, dengan asumsi peserta diklat telah memahami karena telah dibahas pada saat diklat. Oleh karena itu, bagi peminat yang bukan peserta diklat, berikut saya bahas: Cara [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=matemania.wordpress.com&amp;blog=2732517&amp;post=346&amp;subd=matemania&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Pada bahasan sebelumnya, <a href="http://cut.ms/blbe" target="_blank">tebak bilangan</a>, saya sudah memberikan tautan (<em>link</em>) untuk meng<a href="http://cut.ms/blbf" target="_blank">unduh</a> atau me<a href="http://cut.ms/blbg" target="_blank">main</a>kan file presentasi tebak bilangan.</p>
<p>Dalam artikel tersebut tidak (atau belum) diuraikan cara memainkan dan cara menebaknya, dengan asumsi peserta diklat telah memahami karena telah dibahas pada saat diklat. </p>
<p>Oleh karena itu, bagi peminat yang bukan peserta diklat, berikut saya bahas:</p>
<h6>Cara Memainkan dan Menebak Bilangan</h6>
<p><strong>Pertama</strong>, minta kesediaan salah seorang peserta didik (atau <em>audiens</em>) menjadi sukarelawan yang akan ditebak <strong>tanggal</strong> dan <strong>bulan</strong> lahirnya. Sampaikan bahwa, Anda akan menayangkan beberapa kartu. Jika ia mendapati <strong>tanggal</strong> (atau <strong>bulan</strong>) lahirnya ditayangkan, minta ia mengatakan “Ada”, sebaliknya katakan “Tidak ada”.</p>
<p><strong>Kedua</strong>, tayangkan kelima kartu, berupa <em>slide</em> presentasi, secara berurutan. Kemudian, mintalah pada sukarelawan mencermati tiap kartu yang ditampilkan. Demi kemudahan penamaan, saya menyebutnya berdasar pada bilangan yang tertera di <strong>sudut</strong> (<strong>pojok</strong>) <strong>kiri atas</strong>, yaitu <strong>kartu-1</strong>, <strong>kartu-2</strong>, <strong>kartu-4</strong>, <strong>kartu-8</strong>, dan <strong>kartu-16</strong>.</p>
<p>Untuk menebaknya, yang perlu Anda lakukan adalah menjumlahkan bilangan yang tertera di <strong>sudut</strong> (<strong>pojok</strong>) <strong>kiri atas</strong> dari tiap-tiap kartu, yaitu <strong>1</strong>, <strong>2</strong>, <strong>4</strong>, <strong>8</strong>, dan <strong>16</strong>. Sebagai contoh, jika <em>audiens</em> menyebutkan “Ada” pada <strong>kartu-1</strong> dan <strong>kartu-16</strong>, maka tanggal lahir <em>audiens</em> adalah 1+16=17.</p>
<p>Nah, mudah bukan.</p>
<p>Bagi Anda yang tertarik untuk mengetahui bagaimana cara membuat kartu, silahkan pelajari <a href="http://cut.ms/blbh" target="_blank">disini</a>.</p>
<p>Selamat belajar dan bermain.</p>
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		<slash:comments>3</slash:comments>
	
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			<media:title type="html">matemania</media:title>
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		<title>HotPotatoes dan SpeQ</title>
		<link>http://matemania.wordpress.com/2011/07/30/hotpotatoes-dan-speq/</link>
		<comments>http://matemania.wordpress.com/2011/07/30/hotpotatoes-dan-speq/#comments</comments>
		<pubDate>Sat, 30 Jul 2011 18:37:57 +0000</pubDate>
		<dc:creator>edyjo</dc:creator>
				<category><![CDATA[Teknologi Informasi]]></category>

		<guid isPermaLink="false">https://matemania.wordpress.com/2011/07/30/hotpotatoes-dan-speq/</guid>
		<description><![CDATA[Berbagi informasi mengenai piranti lunak (software) yang bisa dimanfaatkan dalam pembelajaran Matematika, dengan Guru Matematika SMA, pada mata diklat Asesmen (Kamis, 28/7) dan mata diklat Matematika SMA (Sabtu, 30/7). Pertama, Hot Potatoes. Piranti lunak yang dapat dimanfaatkan untuk mengembangkan media evaluasi pembelajaran online. Dapat diunduh (download) gratis untuk kepentingan pembelajaran yang tidak bersifat komersial. The [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=matemania.wordpress.com&amp;blog=2732517&amp;post=345&amp;subd=matemania&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Berbagi informasi mengenai piranti lunak (<em>software</em>) yang bisa dimanfaatkan dalam pembelajaran Matematika, dengan Guru Matematika SMA, pada mata diklat Asesmen (Kamis, 28/7) dan mata diklat Matematika SMA (Sabtu, 30/7).</p>
<p>Pertama, <a href="http://cut.ms/bla3" target="_blank">Hot Potatoes</a>. Piranti lunak yang dapat dimanfaatkan untuk mengembangkan media evaluasi pembelajaran <em>online</em>. Dapat diunduh (<em><a href="http://cut.ms/bla4" target="_blank">download</a></em>) gratis untuk kepentingan pembelajaran yang tidak bersifat komersial.</p>
<p><img src="http://hotpot.uvic.ca/images/hpheader6.gif" width="306" height="68" /></p>
<blockquote><p>The Hot Potatoes suite includes six applications, enabling you to create interactive multiple-choice, short-answer, jumbled-sentence, crossword, matching/ordering and gap-fill exercises for the World Wide Web. Hot Potatoes is freeware, and you may use it for any purpose or project you like. It is not open-source.</p>
</blockquote>
<p>Kedua, <a href="http://cut.ms/bla5" target="_blank">SpeQ Mathematics</a>. Piranti lunak yang dapat dimanfaatkan, antara lain, untuk menyelesaikan permasalahan Kombinatorika (bahasan pada saat diklat).</p>
<blockquote><p>SpeQ is a small, extensive mathematics program with a simple, intuitive interface. All calculations are entered in a sheet. In there you can freely add, edit and execute calculations. SpeQ supports all common functions, constants, and units. Furthermore, you can define custom variables and functions, and plot graphs of your functions.</p>
</blockquote>
<p><img src="http://www.speqmath.com/img/screenshot3.png" width="273" height="201" /></p>
<p>Dapat diunduh (<em>download</em>) gratis, dalam format file <a href="http://cut.ms/bla6" target="_blank">executable</a> atau <a href="http://cut.ms/bla7" target="_blank">zip</a>.</p>
<p>Keduanya freeware. Silahkan diunduh untuk dimanfaatkan.</p>
<p>Demikian info, mudah-mudahan bermanfaat. </p>
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		<title>Info</title>
		<link>http://matemania.wordpress.com/2011/07/28/info/</link>
		<comments>http://matemania.wordpress.com/2011/07/28/info/#comments</comments>
		<pubDate>Thu, 28 Jul 2011 20:19:48 +0000</pubDate>
		<dc:creator>edyjo</dc:creator>
				<category><![CDATA[Tips]]></category>

		<guid isPermaLink="false">https://matemania.wordpress.com/2011/07/28/info/</guid>
		<description><![CDATA[Kamis sore, 28 Juli 2011, ketika akan menjadi instruktur di kelas Guru Matematika SMA, disapa oleh salah seorang peserta dari kelas Guru Matematika SMP. Intinya, beliau menyampaikan sering mengakses blog edywihardjo untuk mempelajari tutorial Flash (yang dimaksud adalah pengembangan media pembelajaran berbasis TI atau pakarTI menggunakan Adobe Flash, red). Namun, belakangan ini “sulit” diakses. Sejak [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=matemania.wordpress.com&amp;blog=2732517&amp;post=330&amp;subd=matemania&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Kamis sore, 28 Juli 2011, ketika akan menjadi instruktur di kelas Guru Matematika SMA, disapa oleh salah seorang peserta dari kelas Guru Matematika SMP. Intinya, beliau menyampaikan sering mengakses blog <a href="http://cut.ms/bk6Y" target="_blank">edywihardjo</a> untuk mempelajari tutorial Flash (yang dimaksud adalah pengembangan media pembelajaran berbasis TI atau pakarTI menggunakan Adobe Flash, red). Namun, belakangan ini “sulit” diakses.</p>
<p>Sejak beberapa waktu lalu, saya juga mengalami hal sama. Awalnya, saya menduga akses Internet saya yang bermasalah, namun ketika Kamis malam (seusai nonton Garuda Indonesia menang) saya coba akses menggunakan Google Chrome, tampil pesan sebagai berikut:</p>
<blockquote><p>Situs web mengalami galat saat mengambil <strong>http://edywihardjo.blog.unej.ac.id/</strong>. Situs web mungkin sedang terganggu karena ada perawatan atau dikonfigurasi secara salah.</p>
</blockquote>
<p>Saya juga mencoba mengakses situs mirror, <a href="http://cut.ms/bk6Z" target="_blank">edyjo</a>, ternyata menampilkan pesan sama. Sehingga, kemungkinan besar server blog yang bermasalah. </p>
<p>Untuk itu, saya menyarankan agar mengakses blog alternatif:</p>
<ul>
<li>blog <a href="http://cut.ms/bk60" target="_blank">pakarTI</a> mengenai pengembangan perangkat ajar berbasis Teknologi Informasi; </li>
<li>blog <a href="http://cut.ms/bk61" target="_blank">matemania</a> bagi pecinta matematika; </li>
<li>blog <a href="http://cut.ms/bk62" target="_blank">rubiks-snake</a> membahas permainan rubiks snake. </li>
</ul>
<p>Demikian info, mudah-mudahan bermanfaat.</p>
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		<title>Tebak Bilangan</title>
		<link>http://matemania.wordpress.com/2011/07/28/tebak-bilangan/</link>
		<comments>http://matemania.wordpress.com/2011/07/28/tebak-bilangan/#comments</comments>
		<pubDate>Thu, 28 Jul 2011 04:18:16 +0000</pubDate>
		<dc:creator>edyjo</dc:creator>
				<category><![CDATA[Matematika Dasar]]></category>
		<category><![CDATA[Tips]]></category>

		<guid isPermaLink="false">https://matemania.wordpress.com/2011/07/28/tebak-bilangan/</guid>
		<description><![CDATA[Artikel ini dimaksudkan sebagai suplemen bagi rekan Guru yang ingin membelajarkan Matematika dengan menyenangkan. Penerapannya, bisa dimanfaatkan untuk menebak tanggal lahir, usia, atau bilangan tertentu, dari 1 hingga 31. Silahkan unduh di sini atau mainkan secara online.<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=matemania.wordpress.com&amp;blog=2732517&amp;post=329&amp;subd=matemania&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Artikel ini dimaksudkan sebagai suplemen bagi rekan Guru yang ingin membelajarkan Matematika dengan <font color="#000000"><strong>menyenangkan</strong></font>.</p>
<p>Penerapannya, bisa dimanfaatkan untuk menebak tanggal lahir, usia, atau bilangan tertentu, dari 1 hingga 31.</p>
<p>Silahkan <a href="http://cut.ms/bk4o" target="_blank">unduh</a> di sini atau mainkan secara <a href="http://cut.ms/bk4p" target="_blank">online</a>.</p>
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		<title>Transportasi Ke Jember</title>
		<link>http://matemania.wordpress.com/2011/07/20/transportasi-ke-jember/</link>
		<comments>http://matemania.wordpress.com/2011/07/20/transportasi-ke-jember/#comments</comments>
		<pubDate>Wed, 20 Jul 2011 03:58:41 +0000</pubDate>
		<dc:creator>edyjo</dc:creator>
				<category><![CDATA[Tips]]></category>

		<guid isPermaLink="false">https://matemania.wordpress.com/2011/07/20/transportasi-ke-jember/</guid>
		<description><![CDATA[&#160; Salah satu alternatif sarana transportasi menuju Jember adalah memanfaatkan jasa travel. Beberapa nama travel dan nomor telponnya –khusus dari Surabaya– saya sertakan: Bali Prima: (031-502 7999) Surya Travel: 031-848 0947 Cipaganti Travel : 031-77 500 000, 031-546 0302 Kisaran harga tiket Rp. 65.000,- Keuntungannya dijemput dan diantar ke lokasi, tidak perlu sarana transportasi tambahan. [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=matemania.wordpress.com&amp;blog=2732517&amp;post=328&amp;subd=matemania&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>&#160;</p>
<p>Salah satu alternatif sarana transportasi menuju Jember adalah memanfaatkan jasa travel. Beberapa nama travel dan nomor telponnya –khusus dari Surabaya– saya sertakan:</p>
<ul>
<li>Bali Prima: (031-502 7999)</li>
<li>Surya Travel: 031-848 0947</li>
<li>Cipaganti Travel : 031-77 500 000, 031-546 0302</li>
</ul>
<p>Kisaran harga tiket Rp. 65.000,- Keuntungannya dijemput dan diantar ke lokasi, tidak perlu sarana transportasi tambahan. Namun, kendalanya, jam pemberangkatan terakhir dari Surabaya, biasanya petang atau malam hari. Dengan asumsi perjalanan lancar, tiba di Jember tengah malam. Sehingga perlu bermalam. Sebagai informasi, beberapa hotel dan penginapan telah di booking untuk peserta PLPG (Pendidikan dan Latihan Profesi Guru) Tahap 4, mulai Senin, 18/7 hingga Selasa, 26/7. Dan satu lagi, pada Minggu, 24/7 di Jember ada event nasional (bahkan internasional), yaitu <a href="http://cut.ms/bkIB" target="_blank">Jember Fashion Carnaval</a>. </p>
<p>Oleh karenanya, Anda bisa datang ke Jember secara bersama-sama mengendarai mobil rental. Kisaran harga sewa perhari, 250-300 ribu. Dengan jarak tempuh 2&#215;125 km, konsumsi bensin, 100-150 ribu. Konsumsi untuk sopir, 50 ribu. Total biaya, maksimal Rp. 500 ribu. Jika mobil dikendarai 7 orang, maka biaya perorang 70 ribuan. </p>
<p>Demikian, informasi alternatif sarana transportasi ke Jember. Saya, mewakili Panitia Seminar Nasional Matematika dan Pendidikan Matematika, mengucapkan selamat menempuh perjalanan, semoga perjalanan Anda lancar, kami menunggu kedatangan Anda.</p>
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